S3Tables / Client / create_table

create_table#

S3Tables.Client.create_table(**kwargs)#

Creates a new table associated with the given namespace in a table bucket.

response = client.create_table(
    tableBucketARN='string',
    namespace='string',
    name='string',
    format='ICEBERG'
)

Parameters:

tableBucketARN (string) –
[REQUIRED]

The Amazon Resource Name (ARN) of the table bucket to create the table in.
namespace (string) –
[REQUIRED]

The namespace to associated with the table.
name (string) –
[REQUIRED]

The name for the table.
format (string) –
[REQUIRED]

The format for the table.

Return type:

dict

Returns:

{
    'tableARN': 'string',
    'versionToken': 'string'
}